3.5.1 \(\int \frac {(a+c x^2)^3}{(d+e x)^4} \, dx\)

Optimal. Leaf size=165 \[ -\frac {4 c^2 d \left (3 a e^2+5 c d^2\right ) \log (d+e x)}{e^7}+\frac {c^2 x \left (3 a e^2+10 c d^2\right )}{e^6}-\frac {3 c \left (a e^2+c d^2\right ) \left (a e^2+5 c d^2\right )}{e^7 (d+e x)}+\frac {3 c d \left (a e^2+c d^2\right )^2}{e^7 (d+e x)^2}-\frac {\left (a e^2+c d^2\right )^3}{3 e^7 (d+e x)^3}-\frac {2 c^3 d x^2}{e^5}+\frac {c^3 x^3}{3 e^4} \]

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Rubi [A]  time = 0.16, antiderivative size = 165, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {697} \begin {gather*} \frac {c^2 x \left (3 a e^2+10 c d^2\right )}{e^6}-\frac {4 c^2 d \left (3 a e^2+5 c d^2\right ) \log (d+e x)}{e^7}-\frac {3 c \left (a e^2+c d^2\right ) \left (a e^2+5 c d^2\right )}{e^7 (d+e x)}+\frac {3 c d \left (a e^2+c d^2\right )^2}{e^7 (d+e x)^2}-\frac {\left (a e^2+c d^2\right )^3}{3 e^7 (d+e x)^3}-\frac {2 c^3 d x^2}{e^5}+\frac {c^3 x^3}{3 e^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + c*x^2)^3/(d + e*x)^4,x]

[Out]

(c^2*(10*c*d^2 + 3*a*e^2)*x)/e^6 - (2*c^3*d*x^2)/e^5 + (c^3*x^3)/(3*e^4) - (c*d^2 + a*e^2)^3/(3*e^7*(d + e*x)^
3) + (3*c*d*(c*d^2 + a*e^2)^2)/(e^7*(d + e*x)^2) - (3*c*(c*d^2 + a*e^2)*(5*c*d^2 + a*e^2))/(e^7*(d + e*x)) - (
4*c^2*d*(5*c*d^2 + 3*a*e^2)*Log[d + e*x])/e^7

Rule 697

Int[((d_) + (e_.)*(x_))^(m_)*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*(a + c*
x^2)^p, x], x] /; FreeQ[{a, c, d, e, m}, x] && NeQ[c*d^2 + a*e^2, 0] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int \frac {\left (a+c x^2\right )^3}{(d+e x)^4} \, dx &=\int \left (\frac {c^2 \left (10 c d^2+3 a e^2\right )}{e^6}-\frac {4 c^3 d x}{e^5}+\frac {c^3 x^2}{e^4}+\frac {\left (c d^2+a e^2\right )^3}{e^6 (d+e x)^4}-\frac {6 c d \left (c d^2+a e^2\right )^2}{e^6 (d+e x)^3}+\frac {3 c \left (c d^2+a e^2\right ) \left (5 c d^2+a e^2\right )}{e^6 (d+e x)^2}-\frac {4 c^2 d \left (5 c d^2+3 a e^2\right )}{e^6 (d+e x)}\right ) \, dx\\ &=\frac {c^2 \left (10 c d^2+3 a e^2\right ) x}{e^6}-\frac {2 c^3 d x^2}{e^5}+\frac {c^3 x^3}{3 e^4}-\frac {\left (c d^2+a e^2\right )^3}{3 e^7 (d+e x)^3}+\frac {3 c d \left (c d^2+a e^2\right )^2}{e^7 (d+e x)^2}-\frac {3 c \left (c d^2+a e^2\right ) \left (5 c d^2+a e^2\right )}{e^7 (d+e x)}-\frac {4 c^2 d \left (5 c d^2+3 a e^2\right ) \log (d+e x)}{e^7}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 197, normalized size = 1.19 \begin {gather*} \frac {-a^3 e^6-3 a^2 c e^4 \left (d^2+3 d e x+3 e^2 x^2\right )-12 c^2 d (d+e x)^3 \left (3 a e^2+5 c d^2\right ) \log (d+e x)+3 a c^2 e^2 \left (-13 d^4-27 d^3 e x-9 d^2 e^2 x^2+9 d e^3 x^3+3 e^4 x^4\right )+c^3 \left (-37 d^6-51 d^5 e x+39 d^4 e^2 x^2+73 d^3 e^3 x^3+15 d^2 e^4 x^4-3 d e^5 x^5+e^6 x^6\right )}{3 e^7 (d+e x)^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + c*x^2)^3/(d + e*x)^4,x]

[Out]

(-(a^3*e^6) - 3*a^2*c*e^4*(d^2 + 3*d*e*x + 3*e^2*x^2) + 3*a*c^2*e^2*(-13*d^4 - 27*d^3*e*x - 9*d^2*e^2*x^2 + 9*
d*e^3*x^3 + 3*e^4*x^4) + c^3*(-37*d^6 - 51*d^5*e*x + 39*d^4*e^2*x^2 + 73*d^3*e^3*x^3 + 15*d^2*e^4*x^4 - 3*d*e^
5*x^5 + e^6*x^6) - 12*c^2*d*(5*c*d^2 + 3*a*e^2)*(d + e*x)^3*Log[d + e*x])/(3*e^7*(d + e*x)^3)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a+c x^2\right )^3}{(d+e x)^4} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(a + c*x^2)^3/(d + e*x)^4,x]

[Out]

IntegrateAlgebraic[(a + c*x^2)^3/(d + e*x)^4, x]

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fricas [B]  time = 0.40, size = 334, normalized size = 2.02 \begin {gather*} \frac {c^{3} e^{6} x^{6} - 3 \, c^{3} d e^{5} x^{5} - 37 \, c^{3} d^{6} - 39 \, a c^{2} d^{4} e^{2} - 3 \, a^{2} c d^{2} e^{4} - a^{3} e^{6} + 3 \, {\left (5 \, c^{3} d^{2} e^{4} + 3 \, a c^{2} e^{6}\right )} x^{4} + {\left (73 \, c^{3} d^{3} e^{3} + 27 \, a c^{2} d e^{5}\right )} x^{3} + 3 \, {\left (13 \, c^{3} d^{4} e^{2} - 9 \, a c^{2} d^{2} e^{4} - 3 \, a^{2} c e^{6}\right )} x^{2} - 3 \, {\left (17 \, c^{3} d^{5} e + 27 \, a c^{2} d^{3} e^{3} + 3 \, a^{2} c d e^{5}\right )} x - 12 \, {\left (5 \, c^{3} d^{6} + 3 \, a c^{2} d^{4} e^{2} + {\left (5 \, c^{3} d^{3} e^{3} + 3 \, a c^{2} d e^{5}\right )} x^{3} + 3 \, {\left (5 \, c^{3} d^{4} e^{2} + 3 \, a c^{2} d^{2} e^{4}\right )} x^{2} + 3 \, {\left (5 \, c^{3} d^{5} e + 3 \, a c^{2} d^{3} e^{3}\right )} x\right )} \log \left (e x + d\right )}{3 \, {\left (e^{10} x^{3} + 3 \, d e^{9} x^{2} + 3 \, d^{2} e^{8} x + d^{3} e^{7}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+a)^3/(e*x+d)^4,x, algorithm="fricas")

[Out]

1/3*(c^3*e^6*x^6 - 3*c^3*d*e^5*x^5 - 37*c^3*d^6 - 39*a*c^2*d^4*e^2 - 3*a^2*c*d^2*e^4 - a^3*e^6 + 3*(5*c^3*d^2*
e^4 + 3*a*c^2*e^6)*x^4 + (73*c^3*d^3*e^3 + 27*a*c^2*d*e^5)*x^3 + 3*(13*c^3*d^4*e^2 - 9*a*c^2*d^2*e^4 - 3*a^2*c
*e^6)*x^2 - 3*(17*c^3*d^5*e + 27*a*c^2*d^3*e^3 + 3*a^2*c*d*e^5)*x - 12*(5*c^3*d^6 + 3*a*c^2*d^4*e^2 + (5*c^3*d
^3*e^3 + 3*a*c^2*d*e^5)*x^3 + 3*(5*c^3*d^4*e^2 + 3*a*c^2*d^2*e^4)*x^2 + 3*(5*c^3*d^5*e + 3*a*c^2*d^3*e^3)*x)*l
og(e*x + d))/(e^10*x^3 + 3*d*e^9*x^2 + 3*d^2*e^8*x + d^3*e^7)

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giac [A]  time = 0.16, size = 192, normalized size = 1.16 \begin {gather*} -4 \, {\left (5 \, c^{3} d^{3} + 3 \, a c^{2} d e^{2}\right )} e^{\left (-7\right )} \log \left ({\left | x e + d \right |}\right ) + \frac {1}{3} \, {\left (c^{3} x^{3} e^{8} - 6 \, c^{3} d x^{2} e^{7} + 30 \, c^{3} d^{2} x e^{6} + 9 \, a c^{2} x e^{8}\right )} e^{\left (-12\right )} - \frac {{\left (37 \, c^{3} d^{6} + 39 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6} + 9 \, {\left (5 \, c^{3} d^{4} e^{2} + 6 \, a c^{2} d^{2} e^{4} + a^{2} c e^{6}\right )} x^{2} + 9 \, {\left (9 \, c^{3} d^{5} e + 10 \, a c^{2} d^{3} e^{3} + a^{2} c d e^{5}\right )} x\right )} e^{\left (-7\right )}}{3 \, {\left (x e + d\right )}^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+a)^3/(e*x+d)^4,x, algorithm="giac")

[Out]

-4*(5*c^3*d^3 + 3*a*c^2*d*e^2)*e^(-7)*log(abs(x*e + d)) + 1/3*(c^3*x^3*e^8 - 6*c^3*d*x^2*e^7 + 30*c^3*d^2*x*e^
6 + 9*a*c^2*x*e^8)*e^(-12) - 1/3*(37*c^3*d^6 + 39*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6 + 9*(5*c^3*d^4*e^2
+ 6*a*c^2*d^2*e^4 + a^2*c*e^6)*x^2 + 9*(9*c^3*d^5*e + 10*a*c^2*d^3*e^3 + a^2*c*d*e^5)*x)*e^(-7)/(x*e + d)^3

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maple [A]  time = 0.05, size = 258, normalized size = 1.56 \begin {gather*} -\frac {a^{3}}{3 \left (e x +d \right )^{3} e}-\frac {a^{2} c \,d^{2}}{\left (e x +d \right )^{3} e^{3}}-\frac {a \,c^{2} d^{4}}{\left (e x +d \right )^{3} e^{5}}-\frac {c^{3} d^{6}}{3 \left (e x +d \right )^{3} e^{7}}+\frac {c^{3} x^{3}}{3 e^{4}}+\frac {3 a^{2} c d}{\left (e x +d \right )^{2} e^{3}}+\frac {6 a \,c^{2} d^{3}}{\left (e x +d \right )^{2} e^{5}}+\frac {3 c^{3} d^{5}}{\left (e x +d \right )^{2} e^{7}}-\frac {2 c^{3} d \,x^{2}}{e^{5}}-\frac {3 a^{2} c}{\left (e x +d \right ) e^{3}}-\frac {18 a \,c^{2} d^{2}}{\left (e x +d \right ) e^{5}}-\frac {12 a \,c^{2} d \ln \left (e x +d \right )}{e^{5}}+\frac {3 a \,c^{2} x}{e^{4}}-\frac {15 c^{3} d^{4}}{\left (e x +d \right ) e^{7}}-\frac {20 c^{3} d^{3} \ln \left (e x +d \right )}{e^{7}}+\frac {10 c^{3} d^{2} x}{e^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2+a)^3/(e*x+d)^4,x)

[Out]

1/3*c^3/e^4*x^3-2*c^3*d/e^5*x^2+3*c^2/e^4*a*x+10*c^3/e^6*d^2*x+3*c*d/e^3/(e*x+d)^2*a^2+6*c^2*d^3/e^5/(e*x+d)^2
*a+3*c^3*d^5/e^7/(e*x+d)^2-3*c/e^3/(e*x+d)*a^2-18*c^2/e^5/(e*x+d)*a*d^2-15*c^3/e^7/(e*x+d)*d^4-12*c^2*d/e^5*ln
(e*x+d)*a-20*c^3*d^3/e^7*ln(e*x+d)-1/3/e/(e*x+d)^3*a^3-1/e^3/(e*x+d)^3*d^2*a^2*c-1/e^5/(e*x+d)^3*a*c^2*d^4-1/3
/e^7/(e*x+d)^3*c^3*d^6

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maxima [A]  time = 1.45, size = 226, normalized size = 1.37 \begin {gather*} -\frac {37 \, c^{3} d^{6} + 39 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6} + 9 \, {\left (5 \, c^{3} d^{4} e^{2} + 6 \, a c^{2} d^{2} e^{4} + a^{2} c e^{6}\right )} x^{2} + 9 \, {\left (9 \, c^{3} d^{5} e + 10 \, a c^{2} d^{3} e^{3} + a^{2} c d e^{5}\right )} x}{3 \, {\left (e^{10} x^{3} + 3 \, d e^{9} x^{2} + 3 \, d^{2} e^{8} x + d^{3} e^{7}\right )}} + \frac {c^{3} e^{2} x^{3} - 6 \, c^{3} d e x^{2} + 3 \, {\left (10 \, c^{3} d^{2} + 3 \, a c^{2} e^{2}\right )} x}{3 \, e^{6}} - \frac {4 \, {\left (5 \, c^{3} d^{3} + 3 \, a c^{2} d e^{2}\right )} \log \left (e x + d\right )}{e^{7}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+a)^3/(e*x+d)^4,x, algorithm="maxima")

[Out]

-1/3*(37*c^3*d^6 + 39*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6 + 9*(5*c^3*d^4*e^2 + 6*a*c^2*d^2*e^4 + a^2*c*e
^6)*x^2 + 9*(9*c^3*d^5*e + 10*a*c^2*d^3*e^3 + a^2*c*d*e^5)*x)/(e^10*x^3 + 3*d*e^9*x^2 + 3*d^2*e^8*x + d^3*e^7)
+ 1/3*(c^3*e^2*x^3 - 6*c^3*d*e*x^2 + 3*(10*c^3*d^2 + 3*a*c^2*e^2)*x)/e^6 - 4*(5*c^3*d^3 + 3*a*c^2*d*e^2)*log(
e*x + d)/e^7

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mupad [B]  time = 0.32, size = 228, normalized size = 1.38 \begin {gather*} x\,\left (\frac {3\,a\,c^2}{e^4}+\frac {10\,c^3\,d^2}{e^6}\right )-\frac {x^2\,\left (3\,a^2\,c\,e^5+18\,a\,c^2\,d^2\,e^3+15\,c^3\,d^4\,e\right )+\frac {a^3\,e^6+3\,a^2\,c\,d^2\,e^4+39\,a\,c^2\,d^4\,e^2+37\,c^3\,d^6}{3\,e}+x\,\left (3\,a^2\,c\,d\,e^4+30\,a\,c^2\,d^3\,e^2+27\,c^3\,d^5\right )}{d^3\,e^6+3\,d^2\,e^7\,x+3\,d\,e^8\,x^2+e^9\,x^3}-\frac {\ln \left (d+e\,x\right )\,\left (20\,c^3\,d^3+12\,a\,c^2\,d\,e^2\right )}{e^7}+\frac {c^3\,x^3}{3\,e^4}-\frac {2\,c^3\,d\,x^2}{e^5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + c*x^2)^3/(d + e*x)^4,x)

[Out]

x*((3*a*c^2)/e^4 + (10*c^3*d^2)/e^6) - (x^2*(3*a^2*c*e^5 + 15*c^3*d^4*e + 18*a*c^2*d^2*e^3) + (a^3*e^6 + 37*c^
3*d^6 + 39*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4)/(3*e) + x*(27*c^3*d^5 + 30*a*c^2*d^3*e^2 + 3*a^2*c*d*e^4))/(d^3*e^
6 + e^9*x^3 + 3*d^2*e^7*x + 3*d*e^8*x^2) - (log(d + e*x)*(20*c^3*d^3 + 12*a*c^2*d*e^2))/e^7 + (c^3*x^3)/(3*e^4
) - (2*c^3*d*x^2)/e^5

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sympy [A]  time = 1.98, size = 238, normalized size = 1.44 \begin {gather*} - \frac {2 c^{3} d x^{2}}{e^{5}} + \frac {c^{3} x^{3}}{3 e^{4}} - \frac {4 c^{2} d \left (3 a e^{2} + 5 c d^{2}\right ) \log {\left (d + e x \right )}}{e^{7}} + x \left (\frac {3 a c^{2}}{e^{4}} + \frac {10 c^{3} d^{2}}{e^{6}}\right ) + \frac {- a^{3} e^{6} - 3 a^{2} c d^{2} e^{4} - 39 a c^{2} d^{4} e^{2} - 37 c^{3} d^{6} + x^{2} \left (- 9 a^{2} c e^{6} - 54 a c^{2} d^{2} e^{4} - 45 c^{3} d^{4} e^{2}\right ) + x \left (- 9 a^{2} c d e^{5} - 90 a c^{2} d^{3} e^{3} - 81 c^{3} d^{5} e\right )}{3 d^{3} e^{7} + 9 d^{2} e^{8} x + 9 d e^{9} x^{2} + 3 e^{10} x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2+a)**3/(e*x+d)**4,x)

[Out]

-2*c**3*d*x**2/e**5 + c**3*x**3/(3*e**4) - 4*c**2*d*(3*a*e**2 + 5*c*d**2)*log(d + e*x)/e**7 + x*(3*a*c**2/e**4
+ 10*c**3*d**2/e**6) + (-a**3*e**6 - 3*a**2*c*d**2*e**4 - 39*a*c**2*d**4*e**2 - 37*c**3*d**6 + x**2*(-9*a**2*
c*e**6 - 54*a*c**2*d**2*e**4 - 45*c**3*d**4*e**2) + x*(-9*a**2*c*d*e**5 - 90*a*c**2*d**3*e**3 - 81*c**3*d**5*e
))/(3*d**3*e**7 + 9*d**2*e**8*x + 9*d*e**9*x**2 + 3*e**10*x**3)

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